If Varsity Tutors takes action in response to Information described below to the designated agent listed below. Or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one Seven dimes would total $0.70, and 14 quarters would total $3.50, bringing the grand total to the correct value of $4.20. If we remember that he had 21 coins in all, that leaves 14 quarters. To solve for, we now simply need to divide both sides by. We then want all of our variables on one side and all of our constants on the other, which we can accomplish by subtracting 525 from both sides. We then want to combine like terms (the ds) Next we use the distributive property to simplify, multiplying the 25 by both the 21 and the. We can write this as the following equation. The sum of these two totals should equal the grand total of $4.20, or 420 cents.
Furthermore, since Jamarcus has quarters each worth 25 cents, the total value of all of his quarters is. Since Jamarcus has dimes and each is worth 10 cents, the total value of his dimes is just. Furthermore, each quarter contributes 25 cents to his total. We know that every dime is worth 10 cents, so every dime Jamarcus has contributes 10 cents towards his $4.20 total. At first that might not seem too helpful, but it actually allows us to solve the problem. Now, the only other piece of information we have is that together all 21 coins add up to $4.20. If we add the number of dimes and quarters, we get 21. Therefore, if Jamarcus hs dimes, he must have quarters. If we want to find the number of quarters, we would subtract the number of dimes from 21, and the number we get would be the number of quarters. Since we don't know how many dimes he has, let's label d as the number of dimes. We know Jamarcus has twenty-one coins, but we don't know how many of each he has. We can solve this problem by setting up an algebra equation.
0 kommentar(er)
